Q: A Program to add to two numbers without using Arithmetic operators.
A: Sum of two bits can be obtained by performing XOR (^) of the two
bits. Carry
bit can be obtained by performing AND (&) of two bits. Above is simple Half Adder
logic that can be used to add 2 single bits. We can
extend this logic
for integers. If x and y don’t have set bits at same position(s),
then
bitwise XOR (^) of x and y gives the sum of x and y. To incorporate
common set bits also, bitwise AND (&) is used. Bitwise AND of x and y
gives all
carry bits. We calculate (x & y) << 1 and add it to
x ^ y to get the required
result.
#include<stdio.h>
int Add(int x, int y)
{
// Iterate till there is no carry
while (y != 0)
{
// carry now contains common set bits of x and y
int carry = x & y;
// Sum of bits of x and y where at least one of the bits is not set
x = x ^ y;
// Carry is shifted by one so that adding it to x gives the required sum
y = carry << 1;
}
return x;
}
int main()
{
printf("%d", Add(15, 32));
return 0;
}
int Add(int x, int y)
{
// Iterate till there is no carry
while (y != 0)
{
// carry now contains common set bits of x and y
int carry = x & y;
// Sum of bits of x and y where at least one of the bits is not set
x = x ^ y;
// Carry is shifted by one so that adding it to x gives the required sum
y = carry << 1;
}
return x;
}
int main()
{
printf("%d", Add(15, 32));
return 0;
}
No comments:
Post a Comment